Tests for Lead(II) Ion

Formation of which complex, among the following, is not a confirmatory test of ${\mathrm{Pb}}^{2+}$ ions

Which one doesn't gives ${\mathrm{Pb}}^{+2}$ test?

The reaction of $\mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2$ and $\mathrm{NaCl}$ in water produces a precipitate that dissolves upon the addition of $\mathrm{HCl}$ of appropriate concentration. The dissolution of the precipitate is due to the formation of

Find the number of compounds which have yellow colour precipitate from the given compounds:

${\mathrm{PbCl}}_2, {\mathrm{Hg}}_2{\mathrm{Cl}}_2, \left[\mathrm{Ag}{\left({\mathrm{NH}}_3\right)}_2\right]\mathrm{Cl}, {\mathrm{SnCl}}_2, {\mathrm{HgI}}_2, \mathrm{PbS}$

Find the number of compounds which have yellow colour precipitate from the given compounds:

${\mathrm{PbCl}}_2, {\mathrm{Hg}}_2{\mathrm{Cl}}_2, \left[\mathrm{Ag}{\left({\mathrm{NH}}_3\right)}_2\right]\mathrm{Cl}, {\mathrm{SnCl}}_2, {\mathrm{HgI}}_2, \mathrm{PbS}$

Balance the chemical equation

$\mathrm{Pb}{\left({\mathrm{CH}}_3\mathrm{COO}\right)}_2 + {\mathrm{H}}_2\mathrm{S} \to \mathrm{PbS}\downarrow + \mathrm{\_\_\_\_\_} {\mathrm{CH}}_3\mathrm{COOH}$

Write the chemical reaction of the product formed by reaction of ${\mathrm{Pb}}^{2+}$ with hydrogen sulphide in acidic medium.

_____ and _____ ions give white precipitates with $\text{NaOH}$ solution which are soluble in excess of the reagent. 

Name the probable cation present in the following observation:

White precipitate insoluble in ${\mathrm{NH}}_4\mathrm{OH}$ but soluble in $\mathrm{NaOH}$.

Read the following sequence of reactions:

What are the compounds $\mathrm{D}$ and $\mathrm{E}$?

Which of the following metal ions does not form a complex with ammonia?

Which of the following combinations in an aqueous medium will give a yellow ppt.?

Cotyledons are also called-

$PbC{l}_2$ is insoluble in cold water. Addition of HCl increases its solubility due to

The ion that can be precipitated by $HCl$ as well as $H_{2}S$ is

Which of the following gives a ppt. with $Pb{\left(N{O}_3\right)}_2$ but not with $Ba{\left(N{O}_3\right)}_2$

Distinguishing reagent between silver and lead salts is

$\left(\mathrm{P}\right)+\mathrm{H}\mathrm{C}\mathrm{l}\to \mathrm{ }\mathrm{Q}\mathrm{ }\left(\mathrm{p}\mathrm{p}\mathrm{t}\right)+{\mathrm{H}\mathrm{N}\mathrm{O}}_3\mathrm{ }\left(\mathrm{Q}\right)+\mathrm{K}\mathrm{I}\mathrm{ }\to \mathrm{Y}\mathrm{e}\mathrm{l}\mathrm{l}\mathrm{o}\mathrm{w}\mathrm{ }\mathrm{p}\mathrm{p}\mathrm{t}$

Therefore $\left(\mathrm{P}\right)$ is

To the $\mathrm{P}\mathrm{b}{\left({\mathrm{N}\mathrm{O}}_3\right)}_2$ solution with dilute ${\mathrm{H}}_2{\mathrm{S}\mathrm{O}}_4$ solution is added gradually, then

A solution of a salt gives a precipitate on treatment with dilute HCl. The precipitate formed is filtered off and treated with NH₃ whereby it turns black. The cation present in the salt is